TEC Thermal Load Calculator

Heat Load · Cooling Power · Thermoelectric Module

1. Active Heat Source (Laser Diode)

V
A
W

2. Temperature Gradient

°C
°C

3. Passive Thermal Leakage

cm²
Please fill in all laser parameters correctly.
Active Heat Load
Passive Heat Load
Total Heat Load (Qc)
Required Temp Diff (ΔT)

How to Calculate TEC Thermal Load

To correctly size a Thermoelectric Cooler (TEC or Peltier module) for a laser diode or optical component, you must calculate the Total Heat Load (Qc). This is the sum of the heat actively generated by your device and the ambient heat passively leaking into your system.

Qactive = (Vop × Iop) − Pout
Active Load (Device Waste Heat)
Qpassive = h × A × ΔT
Passive Load (Thermal Leakage)
Qc = Qactive + Qpassive
Total Required Cooling Capacity (Watts)
3D exploded diagram of a TEC thermoelectric cooling system showing tec thermal load on top, TEC Peltier module in the middle with P-N pellets, heatsink with fins at the bottom, thermistor probe, and heat flux arrows for active laser heat and passive ambient leakage
Figure 1: Exploded view of a TEC cooling stack. The total heat load on the cold plate (Qc) is the sum of active heat from the laser diode (Qactive) and passive ambient leakage (Qpassive). The TEC module pumps this heat to the heatsink, which dissipates Qc + PTEC to the environment.

Understanding the Variables

  • Vop & Iop Electrical Input: The operating voltage and current driving the laser diode.
  • Pout Optical Output: The useful optical power emitted by the laser. This energy leaves the system and does not need to be cooled.
  • h Convection Coefficient: The rate of thermal transfer between the cold plate and the environment.
  • A Surface Area: The total exposed area of the cooled components.
  • ΔT Temperature Gradient (Th − Tc): The difference between the hot ambient environment and your target cold temperature.
TEC Efficiency (COP) Remember that TECs are inefficient (typically operating at a COP of ~0.5). If your calculated total load (Qc) is 10W, your TEC will likely consume roughly 20W of electrical power to move that heat.
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